Photoelectric Effect and electrons

[Jules18]

A photoelectric experiment was performed by separately shining a laser at 450 nm (blue light) and a laser at 560 nm (yellow light) on a clean metal surface. Both wavelengths are above the theshold wavelength for the metal, and the same amount of energy is delivered to the metal surface by each laser.

Which laser would shed more electrons, and which laser would shed electrons with the most kinetic energy?

The answer key says the 450 nm (blue) light would make electrons with the most KE, which I get.
But then it says that the yellow 560 nm light would shed more electrons, which makes no sense to me because I thought the # of e- only depended on the intensity of the light and the question says the same amt. of energy was delivered by each laser.
Is the answer key wrong?

 

[mgb_phys]

I thought the # of e- only depended on the intensity of the light

The number of electrons depends on the number of photons

and the question says the same amt. of energy was delivered by each laser.

Yes, how is energy related to number of photons?

 

[Jules18]

ooohhh so for the same amount of energy to be transferred with the 560 nm light, more photons would have to be used?
so more electrons would be released from the metal?

 

[mgb_phys]

Yes for the same power,the laser with the longer wavelength generates more photons.

 

[Jules18]

that was a tricky question.