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Photons emitted by an accelerated charge

  1. Jun 24, 2012 #1
    Almost everyone is familiar with the sentence "accelerated charges radiate em waves".

    Nevertheless, if you are asked to derive this starting from Maxwell's equations, you might find it difficult. Surely the radiation pattern depends on the history of the motion of the charge.

    Then, there comes an even harder problem: Consider the quantum-mechanical problem of the em field coupled to a 4-current corresponding to the accelerated motion of the charge. Treat this as a classical source term, without considering the dynamics of the charge. Can we find the differential cross-section of photons with a particular frequency and polarization being radiated in a particular direction?

    Finally, this cross section is some sort of probability. Suppose a photon is detected. Will this alter the field in some way, similar to the disturbance of quantum particles by measuring their position/momentum, and, if so, how?
     
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  3. Jun 30, 2012 #2
    This is too good a question to disappear without response. One place to start would be the QM savy chapter 16 of Jackson's "Classical Electrodynamics" which takes a fairly thorough study of radiation reaction. But Jackson begins the chapter with the caveat that a fully satisfactory understanding cannot be found at this point because that would entail a better understanding of elementary particles and what their self energy is and how that affects radiation.

    I'd interpret that remark to mean that the physics of elementary particles is developed around the idea of symmetries in spatially extended fields that have different qualities in different types of particles. The creation and annihilation of all types of particles, even with fractional charges, is well described but I've never seen an attempt made at determining boundary conditions for the fields comprising the particles. Boundary conditions would enclose the energy of the particle in a way that could give it qualities of self energy.

    De Broglie, in the context of Wave Mechanics, has expressed that problem in the fact that, with no boundary conditions, all waves associated with particles would very quickly dissipate. The overlooked importance of Mossoti's definition of charge is brought to bear on this especially well in that his definition expresses charge in terms of a boundary condition.
     
  4. Jun 30, 2012 #3

    Bill_K

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    Actually no, it does not depend at all on the history. And the only boundary condition needed is the retarded one. If you take a look in Jackson, Chap 14, the Lienard-Weichert potentials for an accelerating charge are given, and they are quite simple. They depend only on the instantaneous location and velocity of the charge at the retarded time.
     
  5. Jun 30, 2012 #4
    But, the retarded time in those equations is found from the condition:
    [tex]
    \vert \mathbf{x} - \mathbf{r}(t_{ret}) \vert = c \, (t - t_{ret})
    [/tex]
    where [itex](\mathbf{x}, t)[/itex] are the space-time coordinates where the potential is calculated, and [itex]\mathbf{r}(t)[/itex] is the equation of motion for the charge.

    As you can see, this is an implicit equation for [itex]t_{ret}(\mathbf{x}, t)[/itex] that strongly depends on the motion of the charge (its history). For complicated motions, it is impossible to solve exactly.
     
  6. Jun 30, 2012 #5
    You may find this paper interesting: "On the radiation from point charges" by H. A. Haus from American Journal of Physics, Volume 54, Issue 12, pp. 1126-1129 (1986)

    http://adsabs.harvard.edu/abs/1986AmJPh..54.1126H

     
  7. Jun 30, 2012 #6

    Bill_K

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    At the observation point P, construct the past null cone. This intersects the world line of the source at exactly one point Q, which is the retarded location of the particle. No "history", only one instant. The fact that you may not be able to write down a simple analytic solution for Q is irrelevant.
     
  8. Jun 30, 2012 #7
    OK, thanks for your help. Have a nice day.
     
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