Photon's emmited by a 100w bulb.

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SUMMARY

A 100W bulb emits 5% of its power, equating to 5W or 5 J/s, in the visible spectrum. To calculate the number of visible photons emitted per second, one must utilize the equation E (per photon) = hf, where h is Planck's constant. However, the specific frequency or wavelength of the emitted light is not provided. It is recommended to use the average wavelength of visible light for calculations, which can yield a reasonable estimate of the photon emission rate.

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  • Understanding of Planck's constant (h)
  • Knowledge of the electromagnetic spectrum, particularly visible light
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  • Basic principles of power and energy conversion
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Seda
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This is my question verbatim:

"If 5% of the power of a 100w bulb is radiated in the visible spectrum, how many visible photons are radiated per second?"

My work:Obviously, 5% of 100w is 5w, or obviously, 5 J/s.So the bulb is emanating 5 J of visble light per second.Now, I could easily solve this if I knew exactly what frequency (or wavelength) of visible light this bulb was emanating, but I don't. If I knew the frequency, I could simply use

E (per photon) = hf where h is Planck's constant.

And then simply do 5 J / E (per photon) = # of photons.But I'm not given a frequency, and wavelength, or even what type of bulb this is.

Any ideas?

Mabye I should use the lowest and highest wavelengths of visible light and just give a range of photons...
 
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For a problem of this sort, just using the wavelength in the middle of the visible range (as an "average" visible photon) is probably sufficient.
 

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