86.9g of liquid water at 304K is heated by 1.75A passing through 24.7Ω for 104s what is the final temp
its been a while since i did physics so bear with me if i get something mixed up here
q=mCs,pΔT q=ItΔψ ψ=pot dif so isnt that just V from v=IR?
also i believe the q=ItΔψ results in units as AVs if A=Cs-1 then we would get CV which is = to 1J???? long shot but maybe im correct
The Attempt at a Solution
assuming the above is true i want to say that Tf=[(I2tR)/(Cs,pm)]+Ti
plugging in a bunch of numbers and if those units worked out how i think i get 325.65K
Does this seem legit?