Physical applications of complex numbers

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Homework Help Overview

The discussion revolves around the physical applications of complex numbers, particularly in relation to the concepts of velocity and speed. Participants are exploring the relationship between the derivative of a complex function and its magnitude, as well as the implications of these concepts in real-world scenarios.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand how to find the magnitude of the derivative of a complex function without having its components. There is a question about the general rule for finding magnitudes in this context, specifically regarding the use of the complex conjugate. Additionally, some participants inquire about the physical distinction between the magnitude of velocity and velocity itself, seeking real-world examples to illustrate these concepts.

Discussion Status

The discussion is active, with participants sharing their thoughts and examples. Some have provided insights into the relationship between speed and velocity, particularly in the context of circular motion. However, there is no explicit consensus on the questions raised, and multiple interpretations are being explored.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information available for discussion. There is an emphasis on understanding definitions and assumptions related to complex numbers and their physical interpretations.

Calpalned
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Homework Statement


upload_2015-10-13_18-59-28.png


Homework Equations


see picture above

The Attempt at a Solution


I can follow most of the steps, but not all. I got confused with finding ##|\frac{dz}{dt}|##. It is easy to derive ##\frac{dz}{dt}## from ##z##. Normally, I would square the two components of ##dz/dt## and take the square root to get the magnitude (velocity), but here I don't have the components. Is it a general rule that if I don't have the components of a vector, to find the magnitude, I multiply by the complex conjugate?
 
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Calpalned said:

Homework Statement


View attachment 90171

Homework Equations


see picture above

The Attempt at a Solution


I can follow most of the steps, but not all. I got confused with finding ##|\frac{dz}{dt}|##. It is easy to derive ##\frac{dz}{dt}## from ##z##. Normally, I would square the two components of ##dz/dt## and take the square root to get the magnitude (velocity), but here I don't have the components. Is it a general rule that if I don't have the components of a vector, to find the magnitude, I multiply by the complex conjugate?
For a complex number z, ##|z| = \sqrt{z \cdot \bar{z}}##
 
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What is the physical difference between ##|\frac{dz}{dt}|## and ##\frac{dz}{dt}## Could you please give a real world example (ie a car, horse, etc moving) Thank you.
 
Calpalned said:
What is the physical difference between ##|\frac{dz}{dt}|## and ##\frac{dz}{dt}## Could you please give a real world example (ie a car, horse, etc moving) Thank you.
A car's speedometer gives the magnitude of the car's velocity. For example, if you drive the car around a circle at a constant speed, the speedometer needle doesn't change. Velocity is a vector quantity, so the direction of the velocity vector is changing while the car is turning, even though the speed (|v|) is not.
 
Mark44 said:
A car's speedometer gives the magnitude of the car's velocity. For example, if you drive the car around a circle at a constant speed, the speedometer needle doesn't change. Velocity is a vector quantity, so the direction of the velocity vector is changing while the car is turning, even though the speed (|v|) is not.
Thank you. I understand now that the magnitude of velocity is speed
 
Note that an object moving around a circle with constant speed has norm of the velocity vector constant so its derivative is 0. But the velocity vector is NOT constant so its derivative, the acceleration vector, is not 0.
 

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