Physical meaning of the equation E = - del V

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Discussion Overview

The discussion revolves around the physical meaning of the equation E = -∇V, exploring the relationship between electric fields and electric potential. Participants examine the conceptual understanding of gradients, equipotential surfaces, and the definitions of electric field and potential energy.

Discussion Character

  • Conceptual clarification
  • Debate/contested
  • Technical explanation

Main Points Raised

  • Some participants propose that the gradient of a function provides a vector perpendicular to its surface, suggesting that the electric field is the negative of this vector related to equipotential surfaces.
  • Others argue that the gradient specifically gives a vector whose magnitude corresponds to the rate of change of the potential, indicating that the electric field's direction is normal to the equipotential surface and its magnitude is the negative rate of change of potential.
  • A participant introduces an analogy using topographical maps to visualize the relationship between the gradient and equipotential surfaces.
  • Another participant emphasizes that the relationship between electric field and potential is derived from definitions of force per unit charge and potential energy per unit charge, challenging the typical presentation in introductory physics.
  • One participant attempts to clarify the understanding by relating the equation to the general relationship between force and potential energy, suggesting that the mathematics is consistent across different fields, such as gravitational fields.

Areas of Agreement / Disagreement

Participants express varying levels of understanding and interpretation of the equation, indicating that there is no consensus on the physical meaning or visualization of the relationship between electric fields and potential. Multiple competing views remain regarding the definitions and implications of the equation.

Contextual Notes

Some participants highlight the potential confusion arising from different presentations of the relationship between electric fields and potentials, suggesting that assumptions about definitions and context may influence understanding.

Flying_Dutchman
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The gradient of a function gives a vector perpendicular to it's surface. So the equation reads electric field is the negative of the vector perpendicular to the equipotential surface. I know electric field and understand potential but I can't physically make sense for the above sentence how LHS is equal to RHS.
Hope anyone will answer .Thank you !
 
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It’s a definition. You may be able to visualize the relationship if you consider a standard topographical map as a two-dimensional analogy: the gradient of the altitude is a vector perpendicular to the contour lines of equal height, and it points in the direction that a ball at that point will naturally roll.
 
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The gradient does not just give any random vector which is perpendicular to the equipotential surface, but specifically the vector whose magnitude is equal to the rate of change of the function in that direction. So perhaps it is a little easier to understand:

The electric field is a vector whose direction is normal to the equipotential surface and whose signed magnitude is equal to the negative rate of change of the potential in that direction.
 
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Flying_Dutchman said:
I know electric field and understand potential but I can't physically make sense for the above sentence how LHS is equal to RHS.

Start by looking at an ideal parallel plate capacitor. What is the relationship between the voltage difference between the plates and the electric field between the plates?
 
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Nugatory said:
It’s a definition.
Not in the way it's usually presented in introductory college-level physics textbooks and courses. Field is defined as force per unit charge and potential is defined as potential energy per unit charge. From there the relationship between field and potential is derived.
 
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Flying_Dutchman said:
The gradient of a function gives a vector perpendicular to it's surface. So the equation reads electric field is the negative of the vector perpendicular to the equipotential surface. I know electric field and understand potential but I can't physically make sense for the above sentence how LHS is equal to RHS.
Hope anyone will answer .Thank u !

I often do not understand this type of question, because you essentially have accepted this in another form. Let me prove it to you.

Multiple both sides by a charge q that is in this E and V fields, i.e. you get

qE = - ∇qV

which is nothing more than

F = - ∇U

where F is the force acting on the charge q, and U is the potential energy. This is the general relationship between the force and the potential energy, i.e. force is the gradient of potential energy field.

Now, do you have a problem having an understanding or a visual picture of this, because you have accepted this already when it is applied to kinematics, such as force in a gravitational field. There is nothing different here, with the mathematics being identical to each other.

Zz.
 

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