Physics concept questions (electric field & potential diff.)

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Homework Help Overview

The discussion revolves around concepts related to electric fields and potential differences in the context of charged plates. Participants explore the effects of distance and the characteristics of the plates on the electric field and potential.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants discuss the implications of treating plates as infinite versus finite in length, questioning how this affects the electric field and potential difference. There are attempts to relate electric field strength to distance and potential using the equation V=Ed, with varying interpretations of how changes in distance and electric field interact.

Discussion Status

Some participants suggest that the electric field remains constant when treating the plates as infinite, while others question this assumption and its implications for potential difference. There is a recognition of the complexity introduced by finite plate lengths, but no consensus has been reached on the specifics.

Contextual Notes

Participants note that the problem constraints include the assumption of infinite plate length and the relationship between electric field strength and distance, which may not be fully defined in the context of the discussion.

catch22
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Homework Statement


upload_2015-11-10_18-58-59.png


Homework Equations

The Attempt at a Solution


1) charges should remain the same since there is no path for them to go anyway.
2) Now, if the panels were of infinite length, I believe the electric field should be the same regardless of distance? But in this case, the panels aren't infinitely long so there are sharp edges at each end and electric fields are stronger at sharp edges so I believe the answer should be : electric field increases.
3) using V=Ed , if d decreases and E increases... I have no idea then because it would depend on the magnitudes of d and E.
 
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#2)
upload_2015-11-10_19-15-12.png


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#2a) the battery maintains the electric potential in each plate so the potential difference should remain the same.

#2b) using V = Ed, if V is constant, d is decreased, E should increase then.

#2c) I guess charges would remain the same since positive charges on the left plate would be require work to reach the positive terminal of the battery? and same goes for the left side.
 

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Here is how I picture this:

upload_2015-11-10_19-37-56.png


using V=Ed, since V is constant, and the distance between the slab of metal and each plate is d/4, E should increase.
 
In respect of the first problem:
catch22 said:
if the panels were of infinite length, I believe the electric field should be the same regardless of distance? But in this case, the panels aren't infinitely long so there are sharp edges at each end and electric fields are stronger at sharp edges
I don't think you are supposed to worry about those details here. Treat the plates as infinite.
Yes, the field should not change. What does that tell you about potential difference?

Also, remember that the potential at any point is the sum of the potentials due to all the different charges. Consider the potential at one plate. As the other plate gets closer, will the potential there change?

For your other problems, please post each in a separate thread. Gets too confused otherwise.
 
haruspex said:
In respect of the first problem:

I don't think you are supposed to worry about those details here. Treat the plates as infinite.
Yes, the field should not change. What does that tell you about potential difference?

Also, remember that the potential at any point is the sum of the potentials due to all the different charges. Consider the potential at one plate. As the other plate gets closer, will the potential there change?

For your other problems, please post each in a separate thread. Gets too confused otherwise.
If the field doesn't change, then V should decrease as d decreases.

but why do we treat the plates as if they were infinitely long? say the plates are 1 meter long, each, would the field still remain the same?
 
catch22 said:
If the field doesn't change, then V should decrease as d decreases.

but why do we treat the plates as if they were infinitely long? say the plates are 1 meter long, each, would the field still remain the same?
Yes, The potential difference should decrease.
The plates are not infinitely long, so the field is a bit more complicated, but I see no reason why it should change the general trend of the answer. You are not given the relationship between the plate lengths and separation, so it is not possible to be more precise.
 
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