Physics homework problem - design a capacitor

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SUMMARY

The discussion focuses on designing a capacitor with a capacitance of 1 µF using a dielectric material with a dielectric constant of 260 and a dielectric strength of 8 MV/m. The maximum voltage the capacitor can handle is 160 volts. The area of the plates is calculated using the formula A = 4πkdC/V, where the distance between the plates is derived from the relationship d = V/E. The final area calculated is 0.113 m², but the dielectric constant and dielectric strength must be incorporated for accurate results.

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  • Understanding of capacitor design principles
  • Familiarity with dielectric materials and their properties
  • Knowledge of the formula A = 4πkdC/V
  • Basic concepts of electric fields and voltage relationships
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Electrical engineers, physics students, and anyone involved in capacitor design and analysis will benefit from this discussion.

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Physics homework problem -- design a capacitor

Homework Statement


An engineer needs to design a capacitor with a capacitance of 1*10-6F using a material with a dielectric constant 260. If the dielectric strength of the material is 8*106 N/C, and the maximum voltage that the capacitor is allowed to handle is 160 volts, what must be the area of the plates?

Homework Equations


Q=CV, C=A/(4πkd)


The Attempt at a Solution



A=4πkdC; everything is known except the distance between plates

V=Ed, d=V/E; V is given

E=kq/r2, r=d

d=kq/V

A=4πk2CQ/V

I got A = .113m2 but I'm not sure If I'm doing it right or not. Could some check it for me please. I did not use the dielectric constant and dielectric strength values.

Thank you
 
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I did not use the dielectric constant and dielectric strength values.
Then you are doing it wrong.

What is important about the maximum voltage?
It is the voltage, above which, the capacitor does something special...
 
Dielectric strength can also be written as[itex]\frac{V}{m}[/itex], and Max Voltage on a capacitor is dielectric strength * distance between the plates.

Hope this helps.
 

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