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vegetto34
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Homework Statement
A 5.00kg hanging block is connected by a string over a light pulley to a 3.00kg block that is sliding on a flat table. The coefficient of friction between the 3.00kg block and the surface is 0.400. The system starts from rest. What is the speed of the 5.00kg block when it has fallen 1.50m?
x1 = 0
x2 = 1.50m
Block 1
m1 = 5.00kg
Block 2
m2 = 3.00kg
coefficient of friction = 0.400
Homework Equations
Block 1
x: Fnet = T1 + Tf = ma
y: Fnet = Fg + N = ma = 0
Block 2
x: Fnet = ma = 0
y: Fnet = T2 + Fg = ma = T2 - mg = ma
The Attempt at a Solution
a = (t1 + tf) / m
a = (t2 + Fg) / m
(t1 + tf) /m = (t2 + Fg) / m
Plug block 2 (x-axis) t2 = ma + mg into block 2 equation
ma + mg + T1 = ma
mg + T1 = ma - ma = 0
T1 = -mg
I don't know if this is right. Does that mean the tension on the sliding surface is equivalent to the negative Fg?