charge (q) in coulombs, can be calculated byt integrating the current (i) in amperes (A) with respect to time. determine the charge on a capacitor as a result of current flowing for 0.03 seconds if:
a. the current is a constant 5mA (0.005A)
b. the current is a function of time given by i=60t^2
i believe q=(i)(t)
The Attempt at a Solution
if current (i) is integrated with respect to time = it^0+1/0+1 = q=i*t^1 = q=(i)(t)
a. i believe to be q=0.005*0.03=0.00015 coulombs
b. however i assume that i need to integrate i=60t^2
but the A/mA is confusing me i think
should it be 20t^3 or 0.02t^3?
and to find the charge do i just multipli the answer by t ? or is there any further calculation needed?
any help would be appreciated