Physics - Simple Harmonic Motion

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SUMMARY

The discussion focuses on a physics problem involving simple harmonic motion, specifically a block of mass 0.5 kg colliding with a massless pan attached to a spring with a spring constant of 32 N/m. The displacement function is established as x(t) = 0.25sin(8t), with a calculated period T of 0.785 seconds. Participants seek assistance on further calculations, specifically the kinetic energy at 4.0 seconds post-collision and the force exerted by the spring at t=1.2 seconds, emphasizing the use of derivatives to find velocity and acceleration.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Knowledge of spring constants and their role in oscillations
  • Familiarity with calculus, particularly derivatives
  • Basic concepts of kinetic energy and forces in physics
NEXT STEPS
  • Calculate kinetic energy using the formula KE = 0.5 * m * v(t)^2
  • Determine acceleration by finding the second derivative of x(t)
  • Analyze the relationship between position, velocity, and force at specific time intervals
  • Explore the implications of angular frequency in simple harmonic motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to enhance their understanding of simple harmonic motion concepts.

nyyfan0729
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A block of mass 0.5kg moving on a horizontal frictionless surface at 2.0 m/s collides with and sticks to a massless pan attached to the end of a horizontal ideal spring whose spring constan is 32 N/m.
a) Determine the function for x(t), the displacement from equilibrium position as a function of time.
I got this to be x(t) = .25sin(8t)

b) What is the period T, of the subsequent oscillations?
I got the period to be .785 sec
I NEED HELP WITH C AND D, WHAT DO I DO?
c) What is the kinetic energy of the mass 4.0 sec after it collides with the spring?

d) What force is exerted by the spring on the block at t=1.2 sec? Which way is the block moving? Explain
 
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If you have x(t), you can get all of the answers our of it. For instance, your w seems to be 8, which is the angular speed and equal to [tex]2 \pi / T[/tex].
For KE, you can simply get the 1st time derivative of x(t), and you have v(t), and calculate [tex]mv(4)^2/2[/tex].
As for the force, 1st time derivative of v(t) gives a(t), and all you need seems to be ma(1.2). Compare the signs of position and force at t=1.2, and you can conclude whether if they're pointing at the same direction or not. Finally, check out the sign of v(1.2) and happy end :)
 

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