Physics student in need of some help

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SUMMARY

This discussion focuses on solving linear motion problems in physics, specifically involving relative motion and acceleration. The example presented involves a scenario where a person attempts to catch a cockroach running away at a speed of 1.50 m/s while moving towards it at 0.80 m/s, starting 0.90 m behind. The key equation used is d = v0 + (1/2)at2, where the distance includes both the initial distance and the distance the cockroach travels. The initial velocity of the person is confirmed to be 0.80 m/s, clarifying the problem setup.

PREREQUISITES
  • Understanding of linear motion concepts
  • Familiarity with kinematic equations
  • Knowledge of relative velocity
  • Basic algebra skills for solving equations
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  • Study kinematic equations in detail, focusing on d = v0 + (1/2)at2
  • Learn about relative motion and how to analyze problems involving two moving objects
  • Practice solving linear motion problems with varying initial velocities and accelerations
  • Explore graphical representations of motion to visualize acceleration and distance
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Physics students, educators, and anyone looking to improve their understanding of linear motion and kinematics in physics.

nyguy
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I'm fairly new here and I was in search of some help to clarify some problems. I know that it may sound very easy to most on this forum but I seem to be having a tough time with straight-line (linear) motion problems. When being asked specific questions in a problem I notice that one has to go beyond what's originally being asked of you. For example, I might be asked to find the acceleration, but I might need to find the time to help solve the puzzle. Also, problems dealing with the acceleration of two bodies can really get to me as well. Here is an example of a problem that I took straight out of my textbook. Please help:

Large cockroaches can run as fast as 1.50m/s in short bursts. Suppose you turn on the light in a cheap motel and see one scurrying directly away from you at a constant 1.50m/s as you move toward it at 0.80m/s. If you start 0.90m behind it, what minimum constant acceleration would you need to catch up with it when it has traveled 1.20m, just short of safety under a counter?

I was having problems determing if 0.80m/s was the man's initial velocity or the final velocity when he turned on the light. Also, 0.90m threw me off a bit. Please help and thanks in advance.
 
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0.8 m/s is the man's initial velocity, it seems to be a straightforward application of the equation relating distance and acceleration:
[tex]\[<br /> d = v_0 + {\textstyle{1 \over 2}}at^2 <br /> \][/tex]

-t will be the time it takes the cockroach to reach its shelter
-distance will be the distance the person needs to travel (.9m+1.2m)
-initial velocity is 0.8 m/s
 

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