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Well, the force on the object cannot be greater 9000N when it decelerates. So the maximum deceleration is when F = 9000N.
F = ma
9000 = 6000a
a = 9000/6000 = 1.5ms-2
v2 = u2 + 2as
Where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.
The acceleration is negative, as it is decelerating and the final velocity is zero, so
u2 = 2as
And
s = u2/2a
So
s = u2/3 = 225/3 = 75 m
F = ma
9000 = 6000a
a = 9000/6000 = 1.5ms-2
v2 = u2 + 2as
Where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.
The acceleration is negative, as it is decelerating and the final velocity is zero, so
u2 = 2as
And
s = u2/2a
So
s = u2/3 = 225/3 = 75 m
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