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## Homework Statement

Suppose a catcher is crouched down behind the plate wen he observes the runner breaking for second. After he gets the ball from the pitcher, he throws as hard as necessary to second base without standing up. If the catcher throws the ball at an angle of 30 degrees from the horizontal so that it is caught at second base at about the same height as that catcher threw it, how much time does it take for the ball to travel the 120 ft from the catcher to second base?

## Homework Equations

v= d/t

The big 5 equations

sine law

cosine law

pythagorus

## The Attempt at a Solution

X = 120 feet

V = velocity at which ball was thrown

Θ = 30 degrees

g = acceleration due to gravity = 32.2 ft/sec^2 (constant)

120 = V^2(sin 2*30)/32.2

V = sqrt (120*32.2/sin 60)

V = 66.80 ft/sec.

T = 120/66.80

T = 1.80 sec.

I'm not sure if this is right...is there an easier solution using the formulas provided above?

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