Physics work problem - mastering physics

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The discussion revolves around calculating the work done by a 15-Newton force using the equation W = F·s·cos(θ). The initial calculation yielded W = 15*cos(140°)*160 = -1838.506, but the user received feedback from Mastering Physics indicating potential errors in rounding or significant figures. A key point raised is the requirement for angle measures to be in radians, which may impact the calculation. Despite this, the user argues that the cosine value should not affect the overall answer. The conversation highlights the importance of precision in calculations and the nuances of using different angle measurement systems in physics problems.
Shayna
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Physics work problem -- mastering physics

Homework Statement


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Find the work W done by the 15-Newton force.

Homework Equations


W=\vec F\cdot\vec s=\left|\vec F\right|\left|\vec s\right|\cos \theta

The Attempt at a Solution


W= 15*cos140*160 = -1838.506
I don't know why mastering physics was telling me "Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures."
 
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I don't know if you already figured this out, but the only thing I can think of (and it's not really even related to the error you were getting) is that Mastering Physics requires angle measures to be in radians.
 


yes but that shouldn't be affecting the answer though, cos140degree = cos(14/9)pai
Thanks though
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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