Physicsline Exam Q3: Transistor Output - Debating Correct Answer

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SUMMARY

The discussion centers on the interpretation of the output voltage in a transistor circuit as presented in Question 3 of the Physicsline Exam. The original answer indicates a voltage shift of -3V, attributed to the removal of the DC component by the output capacitor. Participants clarify that if the input signal is zero, the output capacitor will not affect the signal, leading to a final output voltage of zero. The confusion arises from understanding the role of the DC voltage provided by the voltage divider and its removal by the capacitor.

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  • Understanding of transistor operation and output characteristics
  • Knowledge of voltage dividers and their impact on DC signals
  • Familiarity with capacitors and their role in AC and DC signal processing
  • Basic concepts of signal clipping and its effects on output waveforms
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  • Study the function of capacitors in AC coupling and DC blocking
  • Learn about voltage divider circuits and their applications in signal processing
  • Explore transistor clipping and its effects on output signals
  • Review the principles of signal analysis in electronic circuits
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Students studying electronics, educators teaching circuit analysis, and anyone seeking to understand the behavior of transistors in signal processing applications.

sanado
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The question being referred to is question 3 on page 8:
http://www.itute.com/physicsline/phys_trial_exam1_2008v2.pdf

Answer referred to is Question 3 Area of Study 2:
http://www.itute.com/physicsline/phys_trial_exam1_2008v2sol.pdf

I don't understand why they get this answer. The answer I am getting is the exact same as them except shifted 3V down. This is because the DC part (given from the voltage divider) gives a middle point of 3V and when this is removed by capacitor 2, it will cause the voltage to be -3V? Can someone please explain why i am wrong and if not, why this answer is correct? Any help is appreciated...
 
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The output capacitor will remove the DC part of the output signal. If the signal is 0 there is no DC part and the capacitor won't remove anything.
 
Okay, so before it enters the final capacitor, would the graph look like a simple straight line, due to clipping. Since this straight line is infact a DC voltage (it doesn't vary) due to the clipping, it is removed by the capacitor and as such, the V out is zero. Is that right?
 

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