1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calculate the output voltage of the circuit

  1. Jan 16, 2012 #1
    thevenin.png adult image hosting

    I am trying to calculate the output voltage of the circuit as viewed between the two nodes + - and then the equivalent resistance of the circuit looking in to the two nodes.
    I have suppressed the voltage source to obtain Req=30k//30k=15k ohms. Vout=-3v.
    Suppressing the current source I obtain Vout=(30/30+30)x12v=6v.
    Veq=-6v+3v=3v
    Req= 15k ohms??

    I don't have solutions to the questions and was hoping someone could tell me if this is correct or not before I attempt any more questions.

    Thanks in advance
     
    Last edited: Jan 16, 2012
  2. jcsd
  3. Jan 16, 2012 #2

    berkeman

    User Avatar

    Staff: Mentor

    Re: Thevinen

    Do you really need to do anything with the sources? A voltage source is effectively a short circuit for impedance calculations, and a current source is an open circuit. That gives you the output impedance part of the answer. Then just write the KCL equation at the output node to calculate the output voltage...
     
  4. Jan 16, 2012 #3
    Re: Thevinen

    That is what I have done by suppressing the voltage and current sources, replacing them with short and open circuits respectively. I am just not sure if I have re-drawn the circuit correctly to which I used to obtain an output of 3v.
     
  5. Jan 16, 2012 #4

    berkeman

    User Avatar

    Staff: Mentor

    Re: Thevinen

    What do you mean re-draw the circuit? What equation did you use to get to Vout = 3V? (and where did the Vout = -3V come from?)
     
  6. Jan 16, 2012 #5
    Re: Thevinen

    The question asks to suppress the voltage current sources individually to find the Vout. So after suppressing the voltage source I have both resistors in parallel i.e 15k ohms multiplied by the current so 3v. Made a mistake with direction of current source that's where I got -3v from.
    I then suppressed the current source and took the Voltage across the 30k ohm resistor at the output, so (30k/30k+30k)x12volts. Summing the two output voltages is then 9volts.

    Sorry if this is quite a basic example, electronics is not my strongest point.
     
  7. Jan 16, 2012 #6

    berkeman

    User Avatar

    Staff: Mentor

    Re: Thevinen

    Ah, I get it now. Yes, that is the correct answer. You can check that it is correct by just writing the KCL equation at the output node -- you only have one variable (Vout), so it's easy to solve the equation to check your work.
     
  8. Jan 16, 2012 #7
    Re: Thevinen

    Thanks very much!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Calculate the output voltage of the circuit
Loading...