Jonny_trigonometry said:
it (linear motion) can only be detected relative to other frames right? If you look at an object moving past you, you can tell it has linear motion w/respect to your space-time coordinates, so there is a space flux moving through the object when you use your coordinates. This space flux causes it to contract and move through time slower.
You could define a "rest frame" if you like, though there's nothing special that singles it out experimentally, and you can define a vector field that gives the velocity of an object relative to this "rest frame".
It's not very clear what you'd do with this, though. The flux through any 3-d surface will be zero. A 2-d surface perpendicular to the vector field will NOT experience any contraction effects, but WILL have a flux. A 2-d surface that is parallel to the velocity WILL have a reduction in area and have ZERO flux.
So you'd only have contraction in a 2-d surface when there is no flux. This doesn't seem especially promising to me for making this idea work.
Basically, it'd really be better if you tried to learn relativity, rather than making up your own theories.
What if you could stay at a specific altitude from the sun without orbiting it, and there was a detector much closer to the sun in the same radial ray, and a detector much further away on the same radial ray. All three positions require a constant thrust to keep you in the same position. Suppose the middle position emmits two photons which travel to the positions close to, and far away from the sun, would the position close to the sun see a blue shift whereas the position far from the sun would see a redshift?
Yes, the photons falling down the gravity well will be blueshifted, and the photons falling upwards will be redshifted.
If this is true (which I'm betting it is), could you then make a principle of equivalence of space flux near the presence of matter?
I don't see any particular reason to try and explain things in this manner.
Sorry, but I'm feeling overdosed on speculation and "what if's" here.
But I can try to say a few things about rotating frames in relativity. The basic tool that describes space-time is the metric. The metric is a tensor. A tensor has no concept of rotation. More specifically, the components of a tensor are unaffected _at the origin of the coordinate system_ by the choice of rotating or non-rotating coordiantes. When you specify a basis of vectors at a point, you specify the values of a tensor quantity. The rotation or lack of rotation of this basis does not affect any of the components of a tensor.
Where rotation first comes into the picture is with the Christoffel symbols, which are not tensors. These Christoffel symbols can tell us whether or not the choice of coordinates we picked is rotating or not rotating, depending on the value of certain components of the symbols at the origin of the coordinates.
Christoffel symbols can be calculated by an appropriate sum of first-order derivatives of the metric tensor.
The presence of rotation in the x-y plane can be identified with non-zero values of the Christoffel symbols \Gamma^x{}_{ty} and \Gamma^y{}_{tx}, for instance.
Physically, given the principle that objects follow geodesics (this is true in GR), these Christoffel symbols correspond to coriolis forces. If an object experiences an acceleration in the x direction that's proportional to it's y velocity, and an inverse acceleration in the y direction that's proportional to it's x velocity, we can say that the system has a component of rotation in the x-y plane.
The Riemann curvature tensor can be defined from the Christoffel symbols, but because it is a tensor, the value of all of its components are independent of rotation around the origin (rotation about another point can be detected, but not rotation around the point where the tensor is measured). The Riemann is composed of second derivatives of the metric tensor, and some non-linear terms that involve the products of two first derivatives.
Einsteins equation then expresses one tensor quantity, the Einstein tensor (derived from the Riemann, a contraction), in terms of another tensor quantity, the stress-energy tensor. By definition, these tensor quantites at a point are not affected by rotation around the origin.