Piecewise continuous -> NO vertical asymptotes

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Discussion Overview

The discussion centers around the properties of piecewise continuous functions, specifically addressing the question of whether such functions can have vertical asymptotes. Participants explore definitions, examples, and implications of piecewise continuity in relation to discontinuities.

Discussion Character

  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant asserts that it is impossible for a piecewise continuous function to have vertical asymptotes, referencing a website for support.
  • Another participant counters that it is not impossible, noting that the linked source states a piecewise continuous function may not have vertical asymptotes and provides an example of one that does not.
  • A further reply suggests that while the source mentions types of discontinuities, it implies that vertical asymptotes are indeed impossible for piecewise continuous functions.
  • Another participant argues that since piecewise continuous functions consist of finite continuous pieces, none of these can have vertical asymptotes, as continuous functions do not exhibit such behavior.
  • One participant introduces the function y = 1/x, which has a vertical asymptote at x = 0, suggesting that definitions matter and that a piecewise continuous function defined for all x can have no vertical asymptote.
  • A later reply discusses the definition of piecewise continuity, indicating that while a function like f(x)=1/x could meet a basic criterion for piecewise continuity, most definitions include restrictions that prevent vertical asymptotes.

Areas of Agreement / Disagreement

Participants do not reach a consensus; multiple competing views remain regarding the relationship between piecewise continuity and vertical asymptotes.

Contextual Notes

Participants express differing interpretations of the definition of piecewise continuity and its implications for vertical asymptotes, highlighting the importance of specific conditions and definitions in this context.

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it's not impossible. you link says a piecewise-continuous function may not have vertical asymptotes, and it gives an example of one that doesn't :wink:
 


fourier jr said:
it's not impossible. you link says a piecewise-continuous function may not have vertical asymptotes, and it gives an example of one that doesn't :wink:

But it then goes on to say that "the only possible types of discontinuities for a piecewise continuous function are removable and step discontinuities." So it seems that vertical asymptotes ARE impossible!
 


"A function made up of a finite number of continuous pieces..."

It is not possible since anyone of these continuous pieces cannot have a single asymptote. Continuous functions that define these pieces are continuous in that they don't have asymptotes.
 


The function y = 1/x for x not zero has a vertical asymptote at x = 0. I don't think you will find any text that will say otherwise. The picture on that website shows a function that is defined for all x. I think what they are trying to say is that a piecewise continuous function that is defined for all x can have no vertical asymptote. Hypotheses matter.
 


It's simply part of the definition.

If you simply defined "piecewise continuous" to mean that a function has finitely many discontinuities, then a function like f(x)=1/x would satisfy that criterion (whether the function exists at x=0, is actually somewhat irrelevant in this case as we could define f(0)=0 for example). And this would give you a piecewise continuous function with a vertical asymptote.

However, most (useful) definitions of piecewise continuity involve other conditions to restrict the function from having asymptotes. If the function is continuous at all but finitely many points, each discontinuity must be isolated, meaning that at a particular discontinuous point x, the right hand and left hand limits of f exist. A typical added restriction is for all right and left hand limits to be finite for all points.
 

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