Piecewise Differentiable Equation?

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SUMMARY

The discussion focuses on determining the constants K and M for the piecewise function h(x) defined as h(x) = kx² + 1 for 0 < x ≤ 2 and h(x) = mx - 3 for 2 < x ≤ 5, ensuring that h is differentiable at x = 2. To achieve differentiability, two conditions must be satisfied: continuity at x = 2, represented by the equation \lim_{x \to 2^-} h(x) = \lim_{x \to 2^+} h(x), and differentiability, represented by \lim_{x \to 2^-} h'(x) = \lim_{x \to 2^+} h'(x). Solving these equations will yield the values of K and M.

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Homework Statement


K and M are constants. If h is differentiable at x=2, what are the values of k and m.
h(x)= kx^2 + 1, 0<x<2
mx - 3, 2<x<5

All of the "<" signs are "less than or equal to"

Homework Equations

Not sure



The Attempt at a Solution

I tried setting the two parts of the function equal to each other and substituting 2 for x, but it doesn't work. Not sure what to do. ANy help would be greatly appreciated!
 
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I think you're on the right track. Saying h is differentiable at x=2 actually gives you 2 conditions:

h is continuous, so \lim_{x \to 2^-} h(x) = \lim_{x \to 2^+} h(x)

h is differentiable, so \lim_{x \to 2^-} h&#039;(x) = \lim_{x \to 2^+} h&#039;(x)

Write out what each of these means using the definition of h, which should give you 2 equations with 2 unknowns.
 

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