Pinball spring problem help me please

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SUMMARY

The pinball machine's ball launcher utilizes a spring with a force constant of 1.10 N/cm to launch a 0.100 kg ball from a 6.00 cm compression. The inclined surface is set at 10.0° to the horizontal. The relevant equations for solving this problem include potential energy (PE = mgy), kinetic energy (KE = 1/2 mv²), and spring potential energy (PE = 1/2 kx²). By applying the conservation of energy principle, specifically PE1 = KE2 + PE2, the launching speed can be accurately calculated.

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Homework Statement



The ball launcher in a pinball machine has a spring that has a force constant of 1.10 N/cm (Fig. P5.71). The surface on which the ball moves is inclined 10.0° with respect to the horizontal. If the spring is initially compressed 6.00 cm, find the launching speed of a 0.100 kg ball when the plunger is released. Friction and the mass of the plunger are negligible.



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The Attempt at a Solution



 
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Have you been able to make a start on this at all? Can you at least identify the relevant equations? You have to show some initial effort or you might not get much help here.
 
PE= mgy
KE=1/2mv^2
PE=1/2kx^2

i know the problem has got to be set up using PE1=KE2+PE2, but I'm at a loss of which equations will work correctly. I've tried a couple and my velocities are all over. Any help would be appreciated.
 

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