Pion decay (tell me if I'm approaching it correctly)

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Homework Help Overview

The problem involves the decay of a neutral pion into two photons, with a focus on determining the pion's velocity based on the energies of the resulting photons. The context is rooted in relativistic physics, specifically conservation laws related to momentum and energy.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply conservation of momentum to find the pion's velocity, questioning if this approach is sufficient. Other participants suggest that both conservation of momentum and conservation of energy equations are necessary, raising questions about the need for multiple equations in solving for the unknowns.

Discussion Status

The discussion is active, with participants exploring the necessity of using both conservation laws. Some guidance has been offered regarding the equations needed to solve the problem, and there is an acknowledgment of the relationship between the energies of the photons.

Contextual Notes

Participants note that there are three equations and three unknowns involved in the problem, specifically mentioning the relationship between the energies of the photons and the implications for the pion's rest mass.

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Homework Statement



A neutral pion may decay into two photons. A particular pion is traveling along the x-axis when it decays into two photos, the first going directly along the +x axis, the second going directly back along the -x axis. The energy of the photons is measured and it is found that E1 is n times more energetic than E2. Find the velocity u of the pion.

Homework Equations



1) relativistic momentum = gamma *m*u where u is velocity, m is mass
2) momentum of a photon is h/wavelength = h*frequency/c (I'm denoting frequency by nu).

The Attempt at a Solution



I tried to do this using conservation of momentum. I'd like to know if my solution is correct.

Pi = Pf (via conservation of momentum for isolated system)

so

gamma*m*u = h*nu1/c - h*nu2/c (the minus sign accounts for the fact that the photons move in opposite directions along the x axis)

but as given above, E1 = n*E2, so

gamma*m*u = h*nu2 (n - 1)/c

Then I solved for u using algebra (I didn't forget about the u in gamma, I squared everything and solved for u afterwards).

Can that be right? Or am I thinking way too simplistically here?
 
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Hi quasar_4! :smile:

(have a nu: ν :wink:)

It's a bit difficult to tell without seeing your final calculations,

but it looks as if you haven't used a conservation of energy equation. :confused:

You need a conservation of momentum equation and a conservation of energy equation, just as in the Newtonian case (and ν needn't come into it). :wink:
 
hello, tiny-tim! :-D

I need both? Hmm, I thought that I could do it just with conservation of momentum OR conservation of energy. We only have one unknown, so two equations and one unknown! What am I missing here? Why do we need to use both the conserved quantities?

(It's been a long, long time since I took any sort of modern physics class... I feel like such a dork for not remembering this!) :redface:
 
There are three equations and three unknowns. The equations are

Momentum Conservation
Energy Conservation
E1=n E2

The unknowns are
u, E1 and E2.

Your answer should come out in terms of n, c and the rest-mass of the pion.
 
Actually, the rest-mass of the pion drops out.
 

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