Real and virtual photons via neutral pion decay

Click For Summary

Homework Help Overview

The discussion revolves around the decay of a neutral pion into photons, focusing on conservation of energy and momentum. The problem is divided into two parts: the first part involves demonstrating that a neutral pion at rest can decay into two real photons, while the second part examines the conditions under which a single photon from the decay would be considered virtual.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conservation of energy and momentum in the context of the pion's decay, with one attempting to derive the energy of the photons from their momentum. Others suggest alternative approaches, such as using the energy-frequency relationship of photons.

Discussion Status

Participants are actively engaging with the problem, exploring different methods to relate the energies and momenta of the photons resulting from the pion's decay. There is a recognition of the need to show how energy is distributed between the photons, and some guidance has been offered regarding momentum conservation in the pion's rest frame.

Contextual Notes

Participants note constraints on the use of conservation of quantum numbers, emphasizing that only energy and momentum conservation should be considered in their reasoning.

padraux3
Messages
3
Reaction score
0
I wasn't sure whether this question should go in advanced or introductory physics but I decided to post here since it doesn't involve any complex maths.

Homework Statement


Part 1
Consider a neutral pion at rest. On the basis of conservation of energy and momentum alone, show that it is possible for the pion to decay into two real photons (ie: two photons that obey the classical energy momentum relation for photons).

Part 2
Show that if a neutral pion decays into a single photon then the photon is virtual.
Hint: Consider the decay in the rest frame of the pion.

Homework Equations


Photon energy = |p|c
E = mc^2
Conservation laws

The Attempt at a Solution


I'm not sure if I've been going about this the right way but I've been trying all day.

Since the pion is at rest its energy is E(pion) = mc^2.
Then by the conservation of energy, the sum of the energies of the two photons is equal to E(pion). Also, the pion has zero momentum so the momentum of the two photons is also zero (thus they are moving at the same speed in opposite directions). From here I've tried to show that the energy of each photon is given by the first equation I listed. I know that the pion's energy should be evenly distributed between the two photons but I'm not sure how to show it.

Thanks in advance.
 
Physics news on Phys.org
Hi padraux3! :wink:

I think you're making this too complicated …

why derive the energy of a photon from its momentum? :confused:

just use energy of photon = h times … ? :smile:

(and I suppose techinically you have to show that all the other quantum numbers, like baryon number, are conserved :wink:)
 
Thanks for your reply.

If I use E = hf then I end up with the equation mc^2 = h(f1+f2) where fi is the frequency of the ith photon and m is the mass of the pion. I don't really understand what I need to show. From the first hint I assumed I needed to show E = |p|c for each photon so that's why I was trying to derive the energy from momentum. I can't use conservation of quantum numbers, only energy and momentum.
 
I don't think you don't need to prove the energy-momentum relation (unless this is an exercise in deriving special relativity from scratch :wink:).

padraux3 said:
I know that the pion's energy should be evenly distributed between the two photons but I'm not sure how to show it.
To show that, you can use momentum conservation in the pion's rest frame. For example, say that photon #1 has energy E1 and momentum p1, and photon #2 has energy E2 and momentum p2. What is p1 + p2? Then use that to show how E1 relates to E2.
 

Similar threads

  • · Replies 33 ·
2
Replies
33
Views
5K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
6
Views
7K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 34 ·
2
Replies
34
Views
4K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K