Piston Pressure: How to Calculate Forces and Work in a Gas Cylinder System

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SUMMARY

The discussion focuses on calculating forces and work in a gas cylinder system with a 16-cm-diameter piston under a pressure of 3.0 atm. The correct force exerted by the gas on the piston is calculated as 6110 N, while the force exerted by the environment is incorrectly calculated as 2040 N. The work done by the gas during expansion is determined to be 611 J. The conversion of atmospheric pressure to Pascals is crucial for accurate calculations, with 1 atm equating to 1.013e5 Pa.

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  • Understanding of pressure calculations using the formula P=F/A
  • Familiarity with work calculations using the formula W=Fd
  • Knowledge of unit conversions, specifically between atmospheres and Pascals
  • Basic principles of gas behavior in a cylinder system
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  • Study the principles of gas laws and their applications in cylinder systems
  • Learn about unit conversions, focusing on pressure units like atm and Pa
  • Explore advanced calculations involving work done by gases in thermodynamic processes
  • Investigate common errors in force calculations in physics problems
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Students studying physics, particularly those focusing on mechanics and thermodynamics, as well as educators seeking to clarify concepts related to gas pressure and work calculations.

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Homework Statement


A cylinder with a 16-cm-diameter piston contains gas at a pressure of 3.0 atm.

A.How much force does the gas exert on the piston?

B.How much force does the environment exert on the piston?

C.The gas expands at constant pressure and pushes the piston out 10 cm. How much work is done by the environment?

D.How much work is done by the gas?

Homework Equations


P=F/A=N/m^2
W=Fd

The Attempt at a Solution


A. F=(.08^2)(pi)(3)(1.013e5)=6110 N [Correct]
B. F=(.08^2)(pi)(1)(1.013e5)=2040 N[Incorrect]
C. [Unable to calculate due to part B]
D. W=(6110)(.1)=611 J[Correct]

Isn't 1 atm the pressure of the environment? Any help would be appreciated.
 
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im pretty sure you have to convert atms to Pa. 1 x 10^5 Pa = 1atm
 
alicemunro said:
im pretty sure you have to convert atms to Pa. 1 x 10^5 Pa = 1atm

I did convert it into Pa 1 atm = 1.013e5

F = (1.013e5 Pa)(.08 m)^2(pi)= 2037 N, I submitted this but it says incorrect.
 
I can't seem to get this right, am I doing something wrong? Please help, its getting frustrating.
 
Anyone?
 

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