Plane & 3D Vector Homework Solution

  • Thread starter Thread starter lpbg
  • Start date Start date
  • Tags Tags
    3d Plane Vector
Click For Summary
SUMMARY

The discussion focuses on solving a 3D vector problem involving the line equation r=<3+2t, 4+2t, -1-t> and its intersections with the yz, zx, and xy planes. The key points include determining the intersection point A at t=-3/2, which results in coordinates A(0, 1, 1/3), and the need to re-parametrize the line with a unit direction vector. The participants also address the challenges of finding the correct direction for the unit vector and ensuring it aligns with the positive x-axis.

PREREQUISITES
  • Understanding of 3D vector equations and parameterization
  • Knowledge of unit vectors and their calculation
  • Familiarity with intersection points of lines and planes in 3D space
  • Basic algebraic manipulation skills for solving equations
NEXT STEPS
  • Learn how to calculate unit vectors from direction vectors
  • Study the concept of parameterization in 3D vector equations
  • Explore methods for finding intersection points between lines and planes
  • Review the geometric interpretation of vectors and their direction in 3D space
USEFUL FOR

Students studying vector calculus, geometry enthusiasts, and anyone tackling 3D vector problems in mathematics or physics.

lpbg
Messages
1
Reaction score
0

Homework Statement


problem 1:
given the straight line r whose equation is r=<3+2t, 4+2t, -1-t>

0.Determine A, intersection of the plane yz
0.1the parameter value at A is t=
0.2therefore A=(...,...,...)

1.we want to re-parametrize r (be u the new parameter) so that:
1.1the new direction vector e be a unit vector, then e = <...,...,...>
1.2 as u increases the x coordinates increases. it follows that e=<...,...,...>
1.3 A be the new origin point. the new equation is: r=<...,...,...>

2. Determine B and C, intersections of r with the zx and xy plane respectively.
2.1 parameter values at the two points are Ub=... Uc=...
2.2 distances AB and AC are therefore dAB=... dAC=...
2.3 Points coordinates are B= (...,...,...) C=(...,...,...)

The Attempt at a Solution


A at x=0 hence 3+2t=0 therefore A at t=-3/2
point A(0,1,1/3)
direction vector d=(2,2,-1)

for 1.1 the formula to be applied is v/|v| but i don't know whether it should be applied to the direction vector or to the original equation. also question 1.2 is problematic for me since i don't understand what is asked for. any help is much appreciated
 
Physics news on Phys.org
For 1.1, if t increases, in what direction does the point r(t) travel? They want a unit vector in this direction.
For 1.2, you may need to flip that vector around so that it points toward the positive x axis.
 

Similar threads

Replies
18
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
17
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K