Planes and parametric equations

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The discussion revolves around solving a linear algebra problem involving a plane represented by the equation r(s,t)=2i + (t-s) j + (1+3s-5t) k. The user is confused about finding the z component of a point (2, -1, z0) on this plane and how to express the plane in parametric form. It is clarified that the plane can be expressed with x = 2, y = t - s, and z = 1 + 3s - 5t, leading to the conclusion that there are infinitely many points along a line with x = 2 and y = -1. The z component can be expressed as z0 = -4 - 2s, indicating that multiple values of s yield different z0 values. Ultimately, the problem does not yield a unique point but rather a line of points on the plane.
grassstrip1
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Hi everyone! I'm having some issues with this problem for linear algebra. I understand parametric equations fairly but I'm confused about the unit vector notation

1) Consider the plane r(s,t)=2i + (t-s) j + (1+3s-5t) k find the z component of the point (2,-1, z0)

For what values of s and t is this the case?

I don't really know how to start the problem because it isn't in vector or parametric form like I'm used to.
 
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grassstrip1 said:
Hi everyone! I'm having some issues with this problem for linear algebra. I understand parametric equations fairly but I'm confused about the unit vector notation

1) Consider the plane r(s,t)=2i + (t-s) j + (1+3s-5t) k find the z component of the point (2,-1, z0)

For what values of s and t is this the case?

I don't really know how to start the problem because it isn't in vector or parametric form like I'm used to.
It's easy enough to get from the vector form to the parametric form of this plane.
Here x = 2, y = t - s, and z = 1 + 3s - 5t, and you're given a point (2, -1, z0).
 
I don't know what you are "used to" but it certainly is in "vector form" and, as Mark44 says, it is easy to convert to parametric form:
x= 2, y= t- s, z= 1+ 3s- 5t. In order to have (x, y, z)= (2, -1, z_0) you must have 2= 2, t- s= -1, and 1+ 3s- 5t= z_0.

Perhaps it is the fact that there is not a single "unique" answer that is bothering you?

There are an infinite number of points, in fact an entire line, with x= 2, y= -1. From t- s= -1, we can get t= s+ 1 and so write z_0= 1+ 3s- 5(s+ 1)= 1+ 3s- 5s- 5= -4- 2s. The set of such points consists of the line x= 2, y= -1, z= -4- 2s, for any s.
 
Thank you for the replies! I left a little something out of the problem, it said find the z component so that it lies on the plane. Wouldn't that make it just one specific point?
 
grassstrip1 said:
Thank you for the replies! I left a little something out of the problem, it said find the z component so that it lies on the plane. Wouldn't that make it just one specific point?
Work the problem through and see.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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