Planes Calculation Help: Find Point of Intersection with Coordinate Planes

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SUMMARY

The discussion focuses on finding the points of intersection of a line with the coordinate planes, specifically using the point P(-3, -4, 3) and a line defined by the parametric equations x=1+6t, y=2+4t, z=3+1t. To find the intersection with the xy-plane, the z-coordinate is set to zero, leading to the equation 1+6t=2+4t, which simplifies to t=1/2. Substituting t back into the equations for x and y yields the coordinates of the intersection points with the xy-plane, yz-plane, and xz-plane.

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Consider the line which passes through the point P(-3, -4, 3), and which is parallel to the line x=1+6t, y=2+4t,z=3+1t

Find the point of intersection of this new line with each of the coordinate planes:

xy-plane:(_,_,_)
yz-plane:(_,_,_)
yz-plane:(_,_,_)

to find xy-plane, I am thinking that i need to set z=0, but I'm not extactly sure how i would solve for the other two points(x & y). can someone help me?
 
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When the line intersects with the xy plane, it will have z=0. Here you can solve for t.
 
1+6t=2+4t
t=1/2

and when i plug that 1/2 back in for the x and y equation, i get the wrong answer. I'm not understanding what you are trying to tell me.
 
Find the equation of the line parallel to the one given that goes through that point first. Then notice that When it intersects the xy plane, the z component of the line will be 0.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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