Plane's new velocity after wind from west

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A plane traveling north at 200 m/s experiences a wind from the west that accelerates it at 15 m/s² for 10 seconds, resulting in a velocity change. The calculated increase in velocity due to the wind is 150 m/s towards the east. Using the Pythagorean theorem, the new resultant velocity is found to be 250 m/s. The final velocity combines the northward and eastward components effectively. The calculations confirm that the plane's new velocity is indeed 250 m/s at an angle northeast.
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1. Homework Statement
A plane is traveling north at 200 meters/second; a wind blows from the west and accelerates the plane at 15m/s^2. If the wind lasts 10 seconds what is the plane's new velocity?

2. Homework Equations
velocity = acceleration*time

3. The Attempt at a Solution
v = (15m/s^2)(10s) = 150 m/s. Is that towards east? I tried doing Pythagorean theorem with 150 m/s as base and 200m/s as the vertical component since the plane was traveling north and got 132m/s for hypotenuse. But that's not one of the answer choices. ?
 
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jff0404 said:
1. Homework Statement
A plane is traveling north at 200 meters/second; a wind blows from the west and accelerates the plane at 15m/s^2. If the wind lasts 10 seconds what is the plane's new velocity?

2. Homework Equations
velocity = acceleration*time

3. The Attempt at a Solution
v = (15m/s^2)(10s) = 150 m/s. Is that towards east? I tried doing Pythagorean theorem with 150 m/s as base and 200m/s as the vertical component since the plane was traveling north and got 132m/s for hypotenuse. But that's not one of the answer choices. ?

Correct, the plane is blown east. Check your math. This is what I got for the hypotenuse.

v_{f}=\sqrt{200^{2}+150^{2}}=250\frac{m}{s}
 
You're right! Thank you.
 
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