Plastic Deformation: Calculating Total Work Done

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SUMMARY

The discussion focuses on calculating the total work done in stretching a metal sample undergoing plastic deformation, specifically from zero extension to 12.0 mm. The correct approach involves treating the area under the stress-strain graph as a trapezium, using the formula for the area of a trapezium to find the work done. The final calculation yields a total work done of 3.55 Joules, which is derived from the sum of the areas before and during deformation. The key takeaway is the importance of correctly interpreting the graph and applying the trapezium rule for accurate results.

PREREQUISITES
  • Understanding of stress-strain graphs in material science
  • Familiarity with the concept of plastic deformation
  • Knowledge of trapezium area calculations
  • Basic principles of work done in physics
NEXT STEPS
  • Study the principles of plastic deformation in metals
  • Learn about stress-strain relationships and their graphical representations
  • Explore advanced techniques for calculating work done in material deformation
  • Investigate the implications of different materials' behaviors under stress
USEFUL FOR

Students in materials science, physics enthusiasts, and engineers involved in mechanical design and analysis will benefit from this discussion.

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Homework Statement


the graph below shows the behaviour of a sample of a metal when it is stretched until it starts to undergo plastic deformation.

image201004270001.jpg


what is the total work done in stretching the sample from zero extension to 12.0mm?
simplify calculation by treating the region xy as a straight line

Homework Equations





The Attempt at a Solution


i have used the formula total work done = area under the graph f-e
550x12x10^-3x0.5=3.3
which I am wrong.
wouldnt figure out the problem
the ans is 3.55J
 
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The problem says to assume x-y is a straight line, not to assume O-y (where O is the origin) is a straight line. Know what I mean?
 
so the area x-y is a trapezium?
using rule of trapezium
0.5x(500+550)x2.0x10^-3
=1.05
plus the area before deformation
500x10x10^-3x0.5=2.5
2.5+1.05=3.55
yeah i got the answer thx
 

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