Plastic strain depens on loading path

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SUMMARY

The discussion centers on the Theory of Plasticity, specifically the calculation of plastic strain based on different loading paths. The user initially struggled with calculating strain for paths (2) and (3) after their teacher demonstrated the process for path (1). The integration formula provided for path (1) was ε11=∫(1/E)dσ11 + ∫[(σ11/S)(σ11dσ11+3σ12dσ12)]/(σ11^2 + 3σ12^2), leading to the result ε11= (Y/E) + (Y/S)ln√2. Ultimately, the user resolved their confusion by recognizing the need to compute the path integration correctly.

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progiangbk
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Hi there,

My teacher gave me a homework, but this Theory of Plasticity is new and difficult to me.

He has calculated the strain according to path (1), now I have to do with the path (2) and (3).

This is what he did with path (1):

ε11=∫(1/E)dσ11 + ∫[(σ11/S)(σ11dσ11+3σ12dσ12)]/(σ11^2 + 3σ12^2)

the first and second terminals for the above integration are (0,Y) and (0,Y/√3)

Finally he got:

ε11= (Y/E) + (Y/S)ln√2

Please help me with path (2) or pah (3) or both, or tell me how to solve it.

Thanks and best regards
 

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I forgot the arrow for path (1) and (2):

Path (1): O => B => A
Path (2): O => C => A
Path (3): O => A
 
oh, i found it already!, just calculate the path integration!

I was confused because i made error in computing integration so the result was different with my teacher. Now everything's done!
 

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