Creating Mohr's strain circle from a strain rosette

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ridiculoid
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Homework Statement


A sample is put in tension and a strain rosette gives the following results:
Handwritten strain rosette diagram with three strain gauge directions at 45 degree angles: Ec = -264x10^-6 vertical, E8 = 25x10^-6 at 45 degrees, EA = 90x10^-6 horizontal.

i) Calculate principal strains and poissons ratio using Mohrs strain circle.
ii) Calculate principal stresses from principal strains and poissons ratio.

Homework Equations


Mohr's strain circle
γ = -lateral strain / axial strain
σx = E / 1 - γ2 (εx + γεy)
σy = E / 1 - γ2 (εy + γεx)
E = 210 GPa

The Attempt at a Solution


I have drawn up Mohr's circle in autocad and found the following results.
Mohr's strain circle construction with a vertical axis line, horizontal axis, and dashed lines labelled εC, εB and εA; marked values -296.5 and 122.5, and angles 32° and 148°.

principal strains = 122.5x10-6 & -296.5x10-6

poissons ratio = -122.5 / -296.5 = 0.413 (this seems too high?)

principal stresses = σx = 11.5kPa (this is supposed to be low as the load is applied in the y direction?)
σy = -62.99MPa (should this be negative if its in tension?)

Im hoping someone can tell me if I am on the right track.

Thanks in advance!
 
Attachments
  • Handwritten strain rosette diagram with three strain gauge directions at 45 degree angles: Ec = -264x10^-6 vertical, E8 = 25x10^-6 at 45 degrees, EA = 90x10^-6 horizontal.
    5JuhSP9.jpg
    12.3 KB · Views: 980
  • Mohr's strain circle construction with a vertical axis line, horizontal axis, and dashed lines labelled εC, εB and εA; marked values -296.5 and 122.5, and angles 32° and 148°.
    lKhvdZx.jpg
    22.4 KB · Views: 995
ridiculoid said:

Homework Statement


A sample is put in tension and a strain rosette gives the following results:
View attachment 231132
i) Calculate principal strains and poissons ratio using Mohrs strain circle.
ii) Calculate principal stresses from principal strains and poissons ratio.

Homework Equations


Mohr's strain circle
γ = -lateral strain / axial strain
σx = E / 1 - γ2 (εx + γεy)
σy = E / 1 - γ2 (εy + γεx)
E = 210 GPa

The Attempt at a Solution


I have drawn up Mohr's circle in autocad and found the following results.
View attachment 231133
principal strains = 122.5x10-6 & -296.5x10-6

poissons ratio = -122.5 / -296.5 = 0.413 (this seems too high?)

principal stresses = σx = 11.5kPa (this is supposed to be low as the load is applied in the y direction?)
σy = -62.99MPa (should this be negative if its in tension?)

Im hoping someone can tell me if I am on the right track.

Thanks in advance!
I confirm your principal strains. As far as the Poisson ratio is concerned, it seems that there is not enough information provided to determine it, unless the loading is uniaxial, and the principal strain in the z direction is also 122.5E-6.