Analyzing Forces in a Platform and Pulley System

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In the discussion about a girl on a platform and pulley system, participants analyze the forces at play when the girl pulls on the rope to accelerate upwards. The key equations involve tension (T) and the net force (F) acting on the system, with an emphasis on understanding how these forces interact. A central point raised is whether the platform will move, with clarification that the upward force from the rope can exceed the downward force from the girl's weight due to the system's configuration. The conversation highlights the importance of recognizing the net upward force required for acceleration. Overall, the discussion aims to clarify the mechanics of the system and resolve confusion about the forces involved.
Paola Cavazos
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A girl stands on a platform and pulley system. The masses of the platform, girl and pulley are M, m and u respectively. The rope is mass-less. Let the girl pull up on the rope so that she accelerates a upwards. What is the tension of the rope? What is the normal force between the person and the platform? WHat is the tension connecting the pulley and the platform? I think that I should start from T - F = ma, but I really am kind of lost. I hope someone can help me find the accurate solution.

I uploaded an image of the exercise. Please help :)
 

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Paola Cavazos said:
I think that I should start from T - F = ma
You should explain your thinking when asking for help. How did you get this equation? What is it saying?
 
I have a small question Nathanael, I'm a bit confused with the problem too. Will the platform even move?? I'm sorry if this is a stupid question!
 
Suraj M said:
I have a small question Nathanael, I'm a bit confused with the problem too. Will the platform even move?? I'm sorry if this is a stupid question!
It's not a stupid question. I can see how one would think the platform may not move, because the harder you pull up on the rope, the harder your feet push down on the platform. But the upwards force on the platform from pulling is greater than the increased force downward from pushing with your feet.
For the platform to move upwards (or more specifically, for it to accelerate upwards) there has to a net upwards force acting on the system. If the other end of the rope was attached to the platform, and the person was pulling up on it, then clearly it could not move upwards. But since the end of the rope is attached to the ceiling, an upwards external force acts on the platform (and person) allowing upwards acceleration.
P.S.
I like your avatar.
 
I'm sorry but i still don't get how the upward force would be more than the downward. Could you explain?
 
Suraj M said:
I'm sorry but i still don't get how the upward force would be more than the downward. Could you explain?
I purposely left the specifics of that detail out so as not to ruin it for the OP :) I will explain it to you in a private message.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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