(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two particles move along an x axis. Position of particle 1 is x = 6t^2 + 3t + 2. The acceleration of particle 2 is given by a = -8t and at t=0, its velocity is 20 m/s. When the velocities of the particles match, what is their velocity?

2. Relevant equations

3. The attempt at a solution

Ok, so I took the derivative of the position function and found it to be v = 12t + 3. Then I took the integral from the acceleration function and found it to be v = -4t^2 + C ( by plugging t=0, I got C = 20). Hence, v = -4t^2 + 20.

Now, I equated both velocity functions and was left with 4t^2 + 12t -17. Does that mean I should solve the quadratic to get two answers--this seems too simple and the problem is supposed to be 3/3 for difficulty...

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# Homework Help: Please check my work on this short calc (?) prob

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