Please help explaining equation of the plane from the book.

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The discussion focuses on deriving the equation of a plane perpendicular to a vector \(\vec k\) and containing its tip, as presented in "Field and Wave Electromagnetics" by Cheng. The equation is established as \(\hat k \cdot \vec R = A\), where \(A\) is a constant. The user initially finds discrepancies between two derived equations: \(x k_x + y k_y + z k_z = kA\) and \(x k_x + y k_y + z k_z = k^2\). Clarification reveals that both equations are equivalent when \(A\) is set to \(k^2\).

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yungman
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This is from "Field and Wave Electromagnetics" by Cheng. I don't understand how this work:

Let

[tex]\vec k \;=\; \hat x k_x + \hat y k_y + \hat z k_z \;\hbox { and }\; \vec R \;=\; \hat x x + \hat y y + \hat z z[/tex]

be position vectors.

Find the equation of the plane perpendicular to [tex]\vec k[/tex] and contain the tip of vector [tex]\vec k[/tex]

ie: plane contain point [itex]P(k_x, k_y, k_z)[/itex]




Let [itex]k^2 = k_x ^2 + k_y ^2 + k_z ^2[/itex].

The book said

[tex]\hat k \cdot \vec R = \hbox { constant }\;.[/tex] is the equation of the plane!

Using the book’s formula and call the constant as A:

[tex]\hat k \cdot \vec R \;=\; \frac { \hat x k_x + \hat y k_y + \hat z k_z }{ k} \cdot (\hat x x + \hat y y + \hat z z) = \frac { x k_x + y k_y + z k_z }{k} = A[/tex]

[tex]\Rightarrow \; x k_x + y k_y + z k_z \;=\; kA[/tex] (1) is equation of plane.






Normal way of finding equation of plane using point normal is

[tex]\vec k \cdot (\vec R - \vec k )=0[/tex]

[tex]\vec k \cdot (\vec R - \vec k ) \;=\; (\hat x k_x + \hat y k_y + \hat z k_z ) \cdot [(\hat x x + \hat y y + \hat z z)\;-\; (\hat x k_x + \hat y k_y + \hat z k_z )][/tex]

[tex]\Rightarrow\; x k_x + y k_y + z k_z = k^2[/tex] (2)




As you can see (1) is not the same as (2)

Can anyone explain to me?
 
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hi yungman! :smile:

the plane has to "contain the tip of vector k" …

ie R = k must work …

so the constant A in the equation k.R = A must be equal to k.k, ie k2

so (1) and (2) are the same, with A = k2 :wink:
 
Thanks Tiny-Tim.
 

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