Please help explaining equation of the plane from the book.

In summary, the conversation discusses finding the equation of a plane perpendicular to a position vector and containing its tip. The book provides a formula for this equation using the dot product, with the constant A representing the squared magnitude of the vector. The formula given in the book is equivalent to the more traditional method of finding the equation of a plane using a point and a normal vector.
  • #1
yungman
5,718
241
This is from "Field and Wave Electromagnetics" by Cheng. I don't understand how this work:

Let

[tex] \vec k \;=\; \hat x k_x + \hat y k_y + \hat z k_z \;\hbox { and }\; \vec R \;=\; \hat x x + \hat y y + \hat z z [/tex]

be position vectors.

Find the equation of the plane perpendicular to [tex] \vec k [/tex] and contain the tip of vector [tex] \vec k [/tex]

ie: plane contain point [itex] P(k_x, k_y, k_z) [/itex]




Let [itex] k^2 = k_x ^2 + k_y ^2 + k_z ^2 [/itex].

The book said

[tex]\hat k \cdot \vec R = \hbox { constant }\;.[/tex] is the equation of the plane!

Using the book’s formula and call the constant as A:

[tex]\hat k \cdot \vec R \;=\; \frac { \hat x k_x + \hat y k_y + \hat z k_z }{ k} \cdot (\hat x x + \hat y y + \hat z z) = \frac { x k_x + y k_y + z k_z }{k} = A[/tex]

[tex] \Rightarrow \; x k_x + y k_y + z k_z \;=\; kA[/tex] (1) is equation of plane.






Normal way of finding equation of plane using point normal is

[tex] \vec k \cdot (\vec R - \vec k )=0[/tex]

[tex] \vec k \cdot (\vec R - \vec k ) \;=\; (\hat x k_x + \hat y k_y + \hat z k_z ) \cdot [(\hat x x + \hat y y + \hat z z)\;-\; (\hat x k_x + \hat y k_y + \hat z k_z )] [/tex]

[tex] \Rightarrow\; x k_x + y k_y + z k_z = k^2 [/tex] (2)




As you can see (1) is not the same as (2)

Can anyone explain to me?
 
Physics news on Phys.org
  • #2
hi yungman! :smile:

the plane has to "contain the tip of vector k" …

ie R = k must work …

so the constant A in the equation k.R = A must be equal to k.k, ie k2

so (1) and (2) are the same, with A = k2 :wink:
 
  • #3
Thanks Tiny-Tim.
 

1. What is the equation of a plane?

The equation of a plane is a mathematical representation that describes the relationship between three variables in three-dimensional space. It is typically written in the form Ax + By + Cz + D = 0, where A, B, and C are constants and x, y, and z are the variables.

2. How is the equation of a plane derived?

The equation of a plane is derived using the normal vector and a point on the plane. The normal vector is perpendicular to the plane and can be calculated using the cross product of two vectors that lie on the plane. Once the normal vector is known, it can be used along with the coordinates of a point on the plane to write the equation in the form Ax + By + Cz + D = 0.

3. What are the variables in the equation of a plane?

The variables in the equation of a plane are x, y, and z, which represent the coordinates of any point on the plane. These variables can take on any real number, and their values determine the position of the point on the plane.

4. How is the equation of a plane used in science?

The equation of a plane is used in many areas of science, including physics, engineering, and mathematics. It is often used to describe the relationship between different variables in three-dimensional space, such as in the study of motion, forces, and geometric shapes.

5. Can the equation of a plane be used to solve real-world problems?

Yes, the equation of a plane can be used to solve various real-world problems, such as determining the angle of incidence and reflection in optics, calculating the trajectory of a projectile, and finding the intersection of two planes. It is a powerful tool that helps scientists and engineers understand and analyze three-dimensional systems and phenomena.

Similar threads

  • Differential Equations
Replies
11
Views
2K
Replies
1
Views
2K
Replies
2
Views
1K
  • Other Physics Topics
Replies
1
Views
3K
  • Calculus and Beyond Homework Help
Replies
9
Views
765
  • Introductory Physics Homework Help
Replies
3
Views
201
  • Introductory Physics Homework Help
Replies
25
Views
271
  • Introductory Physics Homework Help
Replies
11
Views
225
  • Introductory Physics Homework Help
Replies
12
Views
198
  • Classical Physics
Replies
13
Views
985
Back
Top