Please help me understand this velocity time graph

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  • Thread starter Thread starter UnD3R0aTh
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    Graph Time Velocity
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SUMMARY

The discussion focuses on interpreting a velocity-time graph in the context of harmonic motion. It establishes that when the acceleration (a) is negative (a < 0), the displacement (x) is positive (x > 0), specifically at the point labeled E on the graph. The conversation emphasizes that while the velocity-time graph indicates changes in position, it does not provide the absolute position of the object. The relationship between displacement and velocity is crucial for understanding the motion depicted in the graph.

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UnD3R0aTh
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can u describe this motion? how is x > 0 at E? how can we tell the sign of x from the graph?
 

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This looks like a harmonic oscillator centered on ##x=0##. In that case, ##a=0## corresponds to ##x=0## and the acceleration is pointing to the left (##a <0##) when the particle is right of ##x=0##. Therefore ##a < 0## means ##x > 0##, which is the case for ##t_\mathrm{E}##.
 
UnD3R0aTh said:
can u describe this motion?
"u" wouldn't, but "you" would describe it by looking at the shape - what shape is it? What class of equations gives that shape?

how is x > 0 at E? how can we tell the sign of x from the graph?
x is the displacement - what is the relationship between the displacement and the velocity?
You cannot actually tell the absolute position of the object just from looking at the v-t graph alone - you can only tell how it changes position.
 

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