Please help me understand where I went wrong in my conversion from Cartesian to polar coordinates

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Homework Help Overview

The discussion revolves around the conversion from Cartesian to polar coordinates, specifically focusing on the application of partial derivatives in this context. Participants are examining the mathematical expressions involved in the transformation and identifying potential errors in the original poster's approach.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Some participants suggest starting from the expressions for partial derivatives in polar coordinates and attempting to express them in terms of Cartesian coordinates. There is a focus on identifying where the original poster's reasoning may have diverged from correct mathematical principles.

Discussion Status

Participants are actively engaging in exploring the original poster's work, with some offering insights into the need for including additional terms in the equations. There is a recognition of potential errors, but no consensus on a specific resolution has been reached yet.

Contextual Notes

The original poster expresses uncertainty about their calculations and seeks clarification on specific steps. There is an indication that certain assumptions may not have been adequately addressed in their approach.

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Homework Statement
I need to convert z component of angular momentum operator (in quantum mechanics) Lz from cartesian to polar coordinates
Relevant Equations
L_z = -i \hbar \frac{\partial}{\partial \phi}
I have done this:
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I can't clearly understand where I went wrong. Any help would be greatly appreciated. Thanks in advance.
 
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I would start from \begin{split}<br /> \frac{\partial}{\partial \rho} &amp;= \frac{\partial x}{\partial \rho}\frac{\partial}{\partial x} + \frac{\partial y}{\partial \rho}\frac{\partial}{\partial y} \\<br /> &amp;= \cos \phi \frac{\partial }{\partial x} + \sin \phi \frac{\partial}{\partial y} \\<br /> \frac{\partial}{\partial \phi} &amp;= \frac{\partial x}{\partial \phi}\frac{\partial}{\partial x} + \frac{\partial y}{\partial \phi}\frac{\partial}{\partial y} \\<br /> &amp;= -\rho \sin \phi \frac{\partial}{\partial x} + \rho \cos \phi \frac{\partial}{\partial y}<br /> \end{split} and solve for \frac{\partial}{\partial \phi} in terms of \frac{\partial}{\partial x} and \frac{\partial}{\partial y}.
 
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pasmith said:
I would start from \begin{split}<br /> \frac{\partial}{\partial \rho} &amp;= \frac{\partial x}{\partial \rho}\frac{\partial}{\partial x} + \frac{\partial y}{\partial \rho}\frac{\partial}{\partial y} \\<br /> &amp;= \cos \phi \frac{\partial }{\partial x} + \sin \phi \frac{\partial}{\partial y} \\<br /> \frac{\partial}{\partial \phi} &amp;= \frac{\partial x}{\partial \phi}\frac{\partial}{\partial x} + \frac{\partial y}{\partial \phi}\frac{\partial}{\partial y} \\<br /> &amp;= -\rho \sin \phi \frac{\partial}{\partial x} + \rho \cos \phi \frac{\partial}{\partial y}<br /> \end{split} and solve for \frac{\partial}{\partial \phi} in terms of \frac{\partial}{\partial x} and \frac{\partial}{\partial y}.
Thanks for help. But I wanted to know where I went wrong. Seems like (I) and (ii) is wrong. But I can't understand why.
 
shp said:
I can't clearly understand where I went wrong. Any help would be greatly appreciated. Thanks in advance.
A partial derivative with respect to rho must also be included into equations.
 
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