Calculating Specific Charge (q/m) for a Charged Particle in a Magnetic Field

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SUMMARY

The discussion focuses on calculating the specific charge (q/m) of a charged particle moving in a magnetic field with a speed of v = 8 x 107 m/s, a magnetic induction B = 0.7 T, and an angle λ = 45° with the magnetic field lines. The relevant formula used is BQv sin(θ) = mv2/R, where R = 4 cm is the radius of the particle's circular path. By rearranging the formula, the specific charge can be determined using the known values of velocity, magnetic field strength, and radius.

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  • Understanding of Lorentz force and its application in magnetic fields
  • Familiarity with centripetal force concepts
  • Basic knowledge of trigonometric functions, specifically sine
  • Ability to manipulate algebraic equations
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Britney2
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A charged particle that moves with the speed v=8x10(7) goes in a magnetic field where B=0.7 T (B is the induction) and it makes an angle λ=45◦ with force lines. How is the specific charge(q/m) if the radius is R=4 cm?
(qvb=mv2/R qvb is the formula of the Lorenc force and mv2/R is the centripetal.)
 
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The force exerted on the charged particle at an angle \theta to a magnetic field of flux density,B, and moving with a velocity,v, provides the centripetal force to keep it moving a circular path.

So that

BQvsin\theta=\frac{mv^2}{r}

Which is the formula you posted in a sense...
 

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