Please help with finding the limit of the integral

[MarkovMarakov]

Homework Statement

I want to show that

$$\lim_{\epsilon\to 0}\int_{-\infty}^{\infty}\int_{-\infty}^{\infty}{\epsilon\over 2\pi [(x-x')^2+(y-y')^2+\epsilon^2]^{3\over2}}f(x,y)\;dx\,dy\,\,=f(x',y')$$? I am not sure what conditions there is on $f(x,y)$, though I do know that $$\int_{-\infty}^{\infty}\int_{-\infty}^{\infty}{z\over 2\pi [(x-x')^2+(y-y')^2+z^2]^{3\over2}}f(x,y)\;dx\,dy$$ is well-defined for all $x,y\in R$ and $z>0$.

Homework Equations

Please see above section.

The Attempt at a Solution

It is possible that we couldchange variables or sth? Or maybe show that in the limit, the green's function is the delta function? Please help!

 

[Dick]

Yes, you need to show that in the limit it is a representation of a delta function. You need to i) as $\epsilon$->0 that that $${\epsilon\over [(x-x')^2+(y-y')^2+\epsilon^2]^{3\over2}}$$
approaches zero unless x=x' and y=y'. And ii) that for fixed $\epsilon$ that the integral of that is 1. Use polar coordinates around the point (x',y'). I think you actually need a bit more than that but that's a good start. To go beyond that I think you do need some conditions on f(x,y).

 

[MarkovMarakov]

Thanks, @Dick . So we are showing that that bit is acting like a distribution, right? What conditions are required for f? Is it enough to have f tending to 0?

 

[Dick]

Thanks, @Dick . So we are showing that that bit is acting like a distribution, right? What conditions are required for f? Is it enough to have f tending to 0?

The main condition you need is that f is continuous at x',y'. And sure, it shouldn't blow up at infinity so fast the integral doesn't exist.