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Please Is there a clear answer to these questions

  1. May 21, 2008 #1
    suppose z=2+3i , w=1-5i
    1)make Compare between z,w

    2)find z!

    3)IzI=sqart root (z^2)
    or IzI=sqart root(zz')
    IzI=sqart root (z^2)=sqart root(zz')

    4) Compare between 1,i

    5) i!=????

    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. May 21, 2008 #2

    Redbelly98

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    Where is your attempt at a solution?
     
  4. May 22, 2008 #3

    Defennder

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    What does this mean?
     
  5. May 22, 2008 #4

    HallsofIvy

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    1. What do you mean by "compare"? Find the difference? Absolute value of difference?

    2. Is "!" supposed to be the factorial? It's only defined for positive integers, not complex numbers.

    3. If, by ', you mean "complex conjugate", then [itex]|z|= \sqrt{zz'}[/itex] which is NOT the same as [itex]\sqrt{z^2}[/itex] unless z is real.
     
  6. May 22, 2008 #5
     
  7. May 22, 2008 #6
    PLEASE:
    What is the meaning of the fifth question?
     

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  8. May 23, 2008 #7
    Please answer
     
  9. May 23, 2008 #8

    Redbelly98

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    The question being asked is:

    5. Suppose f(z) = 3xy + i(x-y^2). Find lim{z -> 3+2i} of f(z), or explain carefully why it does not exist.

    I am guessing that z=x+iy. I.e. z=3+2i means x=3 and y=2. However, this makes the question rather easy, just plugging in x=3 and y=2 into the given expression. If they mean something else I don't know what that is.
     
  10. May 23, 2008 #9

    Redbelly98

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    I am unaware of any definition of "less than" or "greater than" concerning complex numbers.
     
  11. May 24, 2008 #10

    HallsofIvy

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    Neither. The field of complex numbers is NOT an "ordered field".
     
  12. May 26, 2008 #11
    Defennder
    HallsofIvy
    Redbelly98
    HallsofIvy

    Thank you very much
    Thank's alot
     
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