The discussion focuses on calculating the change in potential energy of a 2.50 kg textbook lowered from a height of 1.81 m to 1.50 m. The correct formula used is ΔPE = mgh, where ΔPE is the change in potential energy, m is mass, g is the acceleration due to gravity (9.80 m/s²), and h is the change in height. The calculation yields a change in potential energy of -7.595 Joules, indicating a loss of potential energy, which is correctly noted by the participants. The suggestion to include units in the final answer is emphasized for clarity.
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Ion1776 said:3. You lower a 2.50 kg textbook (remember when textbooks used to be made out of paper instead of being digital?) from a height of 1.81 m to 1.50 m. What is its change in potential energy?
1.50-1.81=-.31
(2.50kg)(9.80)(-.31)
=-7.595?