- #1
nesan
- 75
- 0
Can someone check my work please, thank you. :)
A hockey player of mass 85 kg traveling at 15 m/s [N] collides with another hockey player of mass 70 kg at 5.0 m/s [E]. If the two hockey players lock skates during the collision and are held together, find the resultant velocity of the pair. Assume there is no friction.
Ʃinitialρ = Ʃfinalρ
3. Solution, I feel like it is wrong because my answer is 0.2 off what it is in the textbook, I have no idea what decimal place they took. :(
(70) * (5) = (155) (v * cosθ)
(85) * (15) = 155(v * sinθ)
---------------------------
350 = (155) (v * cosθ)
1275 = 155(v * sinθ)
------------------
sqrt((350)^2 + (1275)^2) ≈ 1322.17
1322.17 / 155 ≈ 8.5 m/s [N15°E]
The answer in the textbook is 8.3 m/s [N16°E]
Someone check if I'm correct please. Thank you. :)<3
Homework Statement
A hockey player of mass 85 kg traveling at 15 m/s [N] collides with another hockey player of mass 70 kg at 5.0 m/s [E]. If the two hockey players lock skates during the collision and are held together, find the resultant velocity of the pair. Assume there is no friction.
Homework Equations
Ʃinitialρ = Ʃfinalρ
3. Solution, I feel like it is wrong because my answer is 0.2 off what it is in the textbook, I have no idea what decimal place they took. :(
(70) * (5) = (155) (v * cosθ)
(85) * (15) = 155(v * sinθ)
---------------------------
350 = (155) (v * cosθ)
1275 = 155(v * sinθ)
------------------
sqrt((350)^2 + (1275)^2) ≈ 1322.17
1322.17 / 155 ≈ 8.5 m/s [N15°E]
The answer in the textbook is 8.3 m/s [N16°E]
Someone check if I'm correct please. Thank you. :)<3