Please tell me the definition of this problem

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Homework Help Overview

The problem involves finding a unique vector that is perpendicular to the curve defined by the equation x² + y² = 100 at the point (6, 8). The context is centered around vector calculus and the concept of gradients.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of the function F and its gradient, with one participant attempting to clarify the calculation of the gradient for the given level surface. Questions arise regarding the correct formulation of F and the interpretation of the gradient in relation to the problem.

Discussion Status

Some participants have provided insights into the gradient calculation and its application to the problem. There is an ongoing exploration of the correct interpretation of the function F and its implications for finding the perpendicular vector. Multiple interpretations of the problem are being considered.

Contextual Notes

One participant notes that the problem was translated from Persian to English, indicating potential nuances in the original phrasing that may affect understanding.

rado5
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Homework Statement



Find the unique vector which is perpendicular on x2+y2=100 at (x0,y0)=(6,8).

Homework Equations



[tex]\nabla[/tex]F[tex]/[/tex] [tex]\left|[/tex] [tex]\nabla[/tex]F [tex]\left|[/tex]

The Attempt at a Solution



I think the solution is [tex]\nabla[/tex]F[tex]/[/tex] [tex]\left|[/tex] [tex]\nabla[/tex]F [tex]\left|[/tex] but I don't know how to calculate [tex]\nabla[/tex]F for x2+y2=100
I know [tex]\nabla[/tex]F=([tex]\partial[/tex]F[tex]/[/tex][tex]\partial[/tex]x,[tex]\partial[/tex]F[tex]/[/tex][tex]\partial[/tex]y,[tex]\partial[/tex]F[tex]/[/tex][tex]\partial[/tex]z)
Please tell me how I can find the answer. What is F here?
 
Last edited:
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F(x,y)=x^2+y^2-100. The level surface is F(x,y)=0. Now do the gradient. Or F(x,y)=x^2+y^2 and the level surface is F(x,y)=100, your choice.
 
So in this case the solution is [tex]\nabla[/tex]F[tex]/[/tex][tex]\left|[/tex][tex]\nabla[/tex]F[tex]\left|[/tex] = (0.6,0.8) Is it correct?
([tex]\nabla[/tex]F=(2x,2y)).
 
rado5 said:
So in this case the solution is [tex]\nabla[/tex]F[tex]/[/tex][tex]\left|[/tex][tex]\nabla[/tex]F[tex]\left|[/tex] = (0.6,0.8) Is it correct?
([tex]\nabla[/tex]F=(2x,2y)).

If you mean to find the unit normal to the circle, sure, that's right.
 
Thank you very much really. I actually translated the problem from persian to English, but I think it is now correct. Again thank you very much for your great generosity.
 

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