(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Three point charges are located at the vertices of an equilateral triangle. The charge at the top vertex of the triangle is -4.4 µC. The two charges q at the bottom vertices of the triangle are equal. A fourth charge 2 µC is placed below the triangle on its symmetryaxis, and experiences a zero net force from the other three charges, as shown in the ﬁgure below. Find q.

One side of the triangle is 7.3m. The distance from 2 µC to the triangle is 4.8m.

-4.4 µC {1}

2 µC {2}

2. Relevant equations

F=kQ1Q2/r^2

E=kQ/r^2

3. The attempt at a solution

F (1 on q)= k (-4.4*10^-6)q/7.3^2

(7.3/2)^2+(4.8)^2=b^2

=6.03

F(2 on q)=k(2*10^-6)q/6.03^2

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# Point charges acting on a point

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