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P1nkButt3rflys

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## Homework Statement

Three point charges are located in an equilateral triangle with side 0.330 cm, where q1 = +8.30 µC, q2 = −8.20 µC, and q3 = +1.90 nC.

A) What is the electric field at the location of q3? Enter the x component, then the y component.

B) What is the force on q3? Enter the x component, then the y component.

DIAGRAM:

http://www.learning.physics.dal.ca/dalphysicslib/Graphics/Gtype51/threechrg1.gif

## Homework Equations

|Fe|= (k*|q1|*|q2|)/r^2

|E|=(k*|Q|)/r^2

k = 8.99*10^9 (N*m^2)/C^2

Fe = Electrostatic force between a pair of charges

r = charge separation

q1, q2 = charge magnitudes

E = electric field

Q = charged object

## The Attempt at a Solution

I've attempted this many ways and have been incorrect each time. I know the angles at the three points of the triangle will be 60deg. Knowing this and that the sides of the triangle are 0.330cm in length I calculated "r" -> the distance in respect to X and Y from q1 to q3 and from q2 to q3.

I got r(1-3x) = 0.165cm and r(1-3y) = 0.286cm and r(2-3x) = 0.165cm and r(2-3y) = 0.286cm.

Any help would be greatly appreciated. Even to just the first portion would help a lot.

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