- #1

- 67

- 0

I don't really understand this question and don't know where to start.

Would I start with the equation

E = ((k)(Q)/r^2

what follows next?

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- Thread starter kbyws37
- Start date

- #1

- 67

- 0

I don't really understand this question and don't know where to start.

Would I start with the equation

E = ((k)(Q)/r^2

what follows next?

- #2

- 400

- 1

- #3

- 67

- 0

It would be Coulomb's law of

F = ((k)(q1)(q2))/(r^2)

So it would be -0.280 times the original r value?

The final answer is 12.8 F but I still don't understand.

- #4

- 400

- 1

O.K., you know that F scales as 1/r^2. When r gets smaller, F must get larger. When r is half it's original value, how much larger does F get?

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