Point charge 2.5 microC is located at x = 0, y = 0.30 m, point charge -2.5 microC is located at x = 0 y = -0.30 m. What are (a)the magnitude and (b)direction of the total electric force that these charges exert on a third point charge Q = 4.5 microC at x = 0.40 m, y = 0?
E = kq/r^2
F = qE =
The Attempt at a Solution
I drew the charges on an x-y graph. Then I tried to find the electric field of a single charge:
E1 = (9x10^9 Nm^2/C)(2.5x10^-6 C)(4.5x10^-6 C)/(0.5^2 m)(0.4/0.5))
E1 = 0.50625 m
I then doubled this value to get 1.0125 m. Which is says is wrong. Any suggestions?