Pointlike charge - electric potential

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SUMMARY

The electric potential at a point 0.80 m away from a point charge of 3.5 mC is calculated using Gauss' Law with the formula V = kQ/R, where k = 9E9 N m²/C². The correct charge value is 3.5 mC, not 3.5 C, which significantly affects the calculation. The resulting electric potential should be approximately 3.9375E10 V when using the correct charge value. The confusion arose from misinterpreting the unit of charge, leading to an incorrect application of the formula.

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  • Familiarity with Gauss' Law
  • Knowledge of unit conversions, specifically milliCoulombs (mC) to Coulombs (C)
  • Basic algebra for manipulating equations
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  • Practice solving problems involving electric potential with various charge values
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hannaps
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This is my first time using a website like this, so I sincerely apologize if I'm posting in the wrong spot, I'm just in a bind/frustrated with this seemingly easy problem.

Homework Statement


What is the electric potential at a point 0.80 m away from a point charge of 3.5m C?

Homework Equations


Gauss' Law V= kQ1/R
K = 9E9
Q1 = 3.5 C
R= .80m

The Attempt at a Solution


As far as I am aware, this is the only way to solve a problem like this and when using the equation given, I get an answer of 3.9375E10 V and LONCAPA (system in which homework is given) continues to say it is incorrect. I've tried converting it to nC as well and it won't work. Should there be another equation that I am missing in order to complete it or is it safe to suggest that system has the wrong answer as the correct one? thanks!
 
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Hi Hannaps, Welcome to Physics Forums.

The formula is correct. Your problem statement lists the electric charge as 3.5 mC. That's milli Coulombs. Try that.

By the way, 3.5 Coulombs in one place would be a mighty big electric charge!
 

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