Points of Inflection on a rational function

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SUMMARY

The discussion focuses on finding the inflection points of the rational function f(x) = (x - 1)/(x² - 4) and using the second derivative test to determine concavity. The second derivative, f''(x) = (2x³ - 6x² + 24x - 8)/(x² - 4)⁴, is derived, but the numerator presents challenges in solving for roots. Attempts to factor and apply the Rational Root Theorem reveal that simple rational roots do not exist, indicating that numerical methods or graphing may be necessary for further analysis.

PREREQUISITES
  • Understanding of rational functions and their properties
  • Knowledge of derivatives and the second derivative test
  • Familiarity with the Rational Root Theorem
  • Basic algebraic manipulation skills for polynomial equations
NEXT STEPS
  • Explore numerical methods for finding roots of polynomials, such as Newton's method
  • Learn about graphing techniques to visualize rational functions and their inflection points
  • Study advanced factoring techniques for cubic polynomials
  • Investigate the use of software tools like Wolfram Alpha for solving complex equations
USEFUL FOR

Students studying calculus, particularly those focusing on polynomial functions and concavity analysis, as well as educators seeking to enhance their teaching methods for rational functions.

Larsani
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Homework Statement



Find the inflection points and use second derivative test to determine where the function is concave up or down

Homework Equations



f(x) = (x - 1)/(x2 - 4)

The Attempt at a Solution



f'(x) = (-x2 + 2x - 4) / (x2 - 4)2

f''(x) = 2x3 - 6x2 +24x -8 / (x2-4)4

This is where I am stuck. I can't solve the numerator set to 0. You can factor out the 2 and that's about it. Cubic that I can't solve. I'm looking at:

x(x2 - 3x +12) = 4

and thinking that maybe I can use the quadratic equation to find when that quadratic = 0 but I don't think that will help me.
 
Physics news on Phys.org
You want to solve [itex]2x^3- 6x^2+ 24x- 8= 0[/itex]? The obvious first thing to do is to divide through by 2 to get [itex]x^3- 3x^2+ 12x- 4= 0[/itex]. Now the only possible rational roots are [itex]\pm 1, \pm 2[/itex], and [itex]\pm 4[/itex]. Trying those in turn, we see that none of them satisfy the equation so there is not any "simple" solution.
 

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