Points of Intersection in Polar Areas

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SUMMARY

The discussion focuses on finding the area of the region that lies inside both curves defined by the equations sin(2∅) and cos(2∅). The key challenge is determining the points of intersection between these two trigonometric functions. The solution involves manipulating the equations to find a single equation using the tangent function, specifically by dividing the first equation by cos(2∅). This approach simplifies the problem and leads to the necessary points of intersection.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sin and cos.
  • Familiarity with the double angle formulas for sine and cosine.
  • Knowledge of solving equations involving trigonometric identities.
  • Basic skills in algebraic manipulation of equations.
NEXT STEPS
  • Study the properties of trigonometric functions and their graphs.
  • Learn how to apply the tangent function in solving trigonometric equations.
  • Explore techniques for finding areas between curves in polar coordinates.
  • Investigate the use of numerical methods for solving complex trigonometric equations.
USEFUL FOR

Mathematics students, educators, and anyone involved in solving trigonometric equations or exploring polar coordinates will benefit from this discussion.

JRangel42
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Homework Statement



The question is to find the area of the region that lies inside both curves. The part I'm specifically having trouble with is finding the points of intersection.

Homework Equations



sin (2∅)

cos (2∅)

The Attempt at a Solution



sin 2∅ = cos 2∅
2 sin ∅ cos ∅ = 1 - sin^2 ∅
2 sin Θ cos Θ + sin^2 Θ = 1
sin Θ(2cos Θ + sin Θ) - 1 = 0
 
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JRangel42 said:

Homework Statement



The question is to find the area of the region that lies inside both curves. The part I'm specifically having trouble with is finding the points of intersection.

Homework Equations



sin (2∅)

cos (2∅)

The Attempt at a Solution



sin 2∅ = cos 2∅
2 sin ∅ cos ∅ = 1 - sin^2 ∅
2 sin Θ cos Θ + sin^2 Θ = 1
sin Θ(2cos Θ + sin Θ) - 1 = 0

You don't need the double angle formulas. Divide both sides of your first equation by cos(2∅) to get a single equation involving the tangent function.
 
Seriously?! Anyway, thanks for the help. (^O^)
 

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