Polar Coordinate Tracking problem

Click For Summary

Homework Help Overview

The problem involves tracking a plane at a constant height and speed using polar coordinates. The original poster seeks to determine the rate of rotation of a tracking dish based on specific parameters, including distance and inclination angle.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss unit conversions and the implications of different interpretations of the distance variable. There are attempts to clarify the relationship between the parameters and the resulting calculations.

Discussion Status

Participants are actively engaging with the problem, offering corrections and alternative interpretations. Some guidance has been provided regarding unit checks and the correct application of variables, but no consensus has been reached on the final answer.

Contextual Notes

There is ambiguity regarding the interpretation of "distance from you," which affects the calculations. Additionally, the relevance of gravitational acceleration in the context of the problem is being questioned.

AirForceOne
Messages
49
Reaction score
0

Homework Statement



You're tracking a plane from the ground. The plane is at a constant height h from the ground, at a distance r from you at the illustrated instant, and at an inclination theta. The plane's speed is constant at 1200km/hr. Find the rate at which your tracking dish must rotate if r=3km and theta=30degrees. Does the acceleration of gravity make any contribution to your answer?

CCunj.png


The attempt at a solution

The correct answer is 0.05 rad/s.

But this is what I got:

lZEvz.jpg


Sorry for the gigantic image!

Thanks.
 
Physics news on Phys.org
Check your units.
 
461.88 rad/hr = 0.1283 rad/s

Thanks for pointing that out. Still wrong though :/
 
You resolved i into er and eθ incorrectly. (Try it with θ=90 degrees, for example.) Also, the r in your expression for V isn't equal to 3 km.
 
Why isn't it 3km?
 
I guess it depends on how you interpret the phrase "distance from you." But if you use r=3000 m, the answer is 0.056 rad/s, which rounds to 0.06 rad/s. If you use 3000 km as the horizontal distance from you, you get 0.048 rad/s, which rounds to the answer you cited.
 
Thank you very much. I got 0.06.

What is the meaning of the second part of the question ("Does the acceleration of gravity make any contribution")?

Thanks again.
 
Would you get a different answer if, say, you were on Mars, where the acceleration of gravity is different?
 

Similar threads

Replies
8
Views
2K
Replies
37
Views
5K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K